(1/4)(x+1)^2+5=7

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Solution for (1/4)(x+1)^2+5=7 equation: 



(1/4)(x+1)^2+5=7

We move all terms to the left:

(1/4)(x+1)^2+5-(7)=0



Domain of the equation: 4)(x+1)^2!=0

x∈R



We add all the numbers together, and all the variables

(+1/4)(x+1)^2+5-7=0

We add all the numbers together, and all the variables

(+1/4)(x+1)^2-2=0

We multiply parentheses ..

(+x^2+1/4*1)^2-2=0

We multiply all the terms by the denominator


(+x^2+1-2*4*1)^2=0

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